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4.9x^2+31x-50=0
a = 4.9; b = 31; c = -50;
Δ = b2-4ac
Δ = 312-4·4.9·(-50)
Δ = 1941
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{1941}}{2*4.9}=\frac{-31-\sqrt{1941}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{1941}}{2*4.9}=\frac{-31+\sqrt{1941}}{9.8} $
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